>Layton
>Spacechem
>Antichamber
>Talos Principle
Help me Ganker, I need more puzzle games. Ones with less obvious or structured puzzles.
>Layton
>Spacechem
>Antichamber
>Talos Principle
Help me Ganker, I need more puzzle games. Ones with less obvious or structured puzzles.
50%
75%
Is there a math field more reddit than probability?
Every fricking question is a
>heh, akshually...
I work in a field where I use probability every day and I don't say this or look like this
the probability is still 1/3.
the probability of the time you chose a box doesn't change just because you ruled one out after the fact.
See also: the lets make a deal door puzzle
>the probability is still 1/3
1/ (2/2 + 1/2 + 0/2 + 0/2 + 0/2+ 0/2 + 0/2 + 0/2 + 0/2 + 0/2) = 2/3
It would still be 50% in your image
they're not asking you the probability that the box will have 2 gold balls, they're asking you the probability that after confirming that one of the ball is golden, the next one also will be
Its 50% because at that point in time, if you've already picked one golden ball, then only 2 possible options remain - the box that has 2 golden balls, and the box that has one of each. Coincidentally enough, that means one chance per ball type, so 50%.
I love that shit but this one ez af
think about the situation where there are only two boxes with one million and one balls in each box. One box has one gold ball and one million silver balls, one has one million and one gold balls
the chance that you pulled the gold ball from the mostly silver box is v. small, the odds of the second ball being gold are nearly 100%
think about the probability of me putting my balls in your mouth
>people with this level of thinking post here
I'm picturing you as a reddit snoy-intellectual. You will NOT respond.
moron
I had a lot of fun with Baba Is You and if you want more adventure than pure puzzle, check out Tunic. I'd also try out TIS-100.
Speaking of, anyone want to help me out and take a crack at my sequence sorter? I've been trying to figure it out on and off since the beginning of October, but I'm not a programmer. I have high confidence it's just the two rightmost nodes that are the issue because I haven't put nearly as much thought into them.
But you get a gold ball every time so it's 1/2 :^)
0%
It is not a possibikity, it is a certainty that My Will assert upon the fakeworld of materia. Also a joker is likeky to swap them out when one isn't looking
The Witness
Damn you, Demiurge, introducing typos into my post when I'm not looking!
probability of the second ball being gold is 1 over the probability of the boxes containing gold.
1 / (0/2 + 1/2 + 2/2) = 2/3
morons
it's true
https://en.wikipedia.org/wiki/Bertrand%27s_box_paradox?useskin=vector
Stephen's Sausage Roll.
You cant see inside so 100%
Since you wont know that I just picked up the same ball from the same box
check mate athetosis
Ghost Trick
If you already got a gold ball, it means it has to be one of the two first boxes, because otherwise you couldn't have gotten a gold ball. Since it's one of the two first boxes, that means the other ball can only be the other gold ball (from the first box) or the silver one (from the second box) So it's 1 in 2 chances. 50%
>I need more puzzle games. Ones with less obvious or structured puzzles.
>Attention grabbing image, irrelevant time wasting question
as is tradition
>put the ball back in the box
>take it out again
100%
are you a genius?!
smartest anon in the thread
2/3 odds you get a gold ball. Out of all gold balls, two have a gold ball as a neighbor and one has a silver ball as a neighbor.
2/3
Name boxes: a b c
Name balls:
a1 a2 | b1 b2 | c1 c2
a1, a2 and b1 are gold, rest are silver.
You have picked a gold ball, so there is 1/3 chance it's a1, 1/3 that a2 and 1/3 b1.
If it's a1 or a2 you have 100% probability of picking gold ball (you pick a2 or a1).
But if it's b1 you will pick b2 (silver) so it's 0%.
1/3 * 100% + 1/3 * 100% + 1/3 * 0% = 1/3+ 1/3 + 0 = 2/3
A mystery
That just proves its 50% it doesn't matter which gold ball
Why wouldn't it matter
There are 3 gold balls.
1 is in a box with a silver ball. The other 2 are in a box with another gold ball.
All 3 are equally likely to draw.
Thus the chance is 2 out of 3.
>All 3 are equally likely to draw.
There are only two options. You're holding the third.
There's 3 possibilities and you picked one of them at random.
You're ether holding box GG or box GS. You've removed a G, there is only G or S remaining. There is only one ball left in the box. Which golden ball you picked is irrelevant.
There's two outcomes (GG or GS) but they don't have the same probability. That's like saying you have a 50% chance of winning the lottery because you can only Win or Lose. Each individual golden ball is equally likely to be chosen, so a box with two is twice as likely to be picked as a box with one.
You are more likely to be holding a gold from the double gggggggll zara bizarr double piss filling xxl
mathgays in here with no sense of logic.
Its asking the chance of pulling a gold ball after youve already pulled one. The third box is out of the equation for this question. Its 50%
Outer Wilds
The Witness
Return of the Obra Din
if you have a friend, We Were Here Together